Molarity Tool

Determine molar concentration from solute mass or amount and solution volume. Find required solute mass or solution volume, solve stock dilution relationships, and estimate mixture concentration using clear results, supporting calculations and concentration comparison charts.

Find molarity from solute mass, molar mass and solution volume.

g/mol
Assumes additive volumes, the same solute and no chemical reaction.
Molarity
0.1000 M
0.1000 mol/L
Concentration visualisation
Calculation details

Table of Contents

  1. How Molarity Tool Works?
  2. Practical Use Cases
  3. Accuracy and Limitations
  4. Frequently Asked Questions (FAQs)
  5. Cite This tool

Highlights

  • Calculate molarity from solute mass or amount.
  • Determine required solute mass or solution volume.
  • Solve for any unknown simple dilution variable.
  • Estimate final molarity when combining two solutions.
  • View concentration charts and export results as CSV, JSON or SVG.

How Molarity Tool Works?

Molarity measures the amount of dissolved solute per volume of the final solution. Enter solute amount directly, or provide solute mass and molar mass to determine the amount first.

C=nV=mMM×V

Here, C is molarity (mol/L), n is solute amount (mol), V is final solution volume (L), m is solute mass (g), and MM is molar mass (g/mol). Rearranging the relationship gives the solute mass needed to prepare a target concentration or the final volume needed for a specified amount.

m=C×V×MMV=nC

For dilution of a single stock solution, the amount of solute is conserved. Any one of the four variables can be determined from the other three. The diluent volume to add is the final volume minus the stock volume.

C1V1=C2V2

When combining two solutions containing the same solute, their solute amounts are added and divided by their combined volume.

Cmix=C1V1+C2V2V1+V2

CalculationKey inputsMain output
MolaritySolute mass and molar mass, or amount; final volumeConcentration (M)
Required massTarget concentration, volume, molar massMass (g)
Required volumeSolute amount or mass, target concentrationVolume (L)
DilutionThree of C₁, V₁, C₂, V₂Missing dilution variable and diluent volume
MixingTwo concentrations and two volumesFinal concentration (M)

The results also show intermediate solute amounts, relevant volume or concentration values, and a comparative concentration chart where applicable.

Practical Use Cases

Students: Work through preparation exercises using a known solute mass, molar mass and final flask volume, then check the resulting molarity against the expected answer.

Laboratory technicians: Find the mass of a reagent needed to prepare a specified volume of solution at a target concentration.

Research scientists: Determine stock volumes and diluent additions for working solutions, or solve for an unknown stock concentration from a dilution relationship.

Biochemistry researchers: Estimate the final concentration after combining two aliquots containing the same dissolved compound.

Chemistry educators: Compare stock, diluted and mixed concentrations visually while explaining conservation of solute amount.

Accuracy and Limitations

Results follow the entered numbers and are displayed with roughly six significant digits; the underlying calculations use JavaScript floating-point arithmetic. Dilution assumes solute is conserved, while mixing assumes the two solutions contain the same solute and that their volumes are additive. The calculations do not account for chemical reactions, precipitation, evaporation, temperature-driven volume changes or experimental measurement uncertainty. Dilution inputs must also describe a genuine dilution, not a concentration increase.

Frequently Asked Questions

Molarity is moles of solute per litre of solution. Molality is moles of solute per kilogram of solvent.

The dissolved solute can change the volume, so molarity is defined using the finished solution rather than the solvent alone.

In an ideal dilution with no losses or reactions, the amount of solute stays constant while its concentration decreases.

Yes. At equal molarity, a larger solution volume contains more moles of solute.

A simple average is valid only when the mixed volumes are equal and additive. Otherwise, use a volume-weighted average for the same solute.

Cite This tool